HOME

Course Chapters

Calculator Fundamentals

Mathematics Review

Basic Concepts

Advanced Concepts


Section Tests

Pre-test

Post-test


Useful Materials

Glossary


Online Calculators

Redox Calculator

Kinetics Arrhenius Calculator

Thermodynamics Calculator

Nuclear Decay Calculator

Linear Least Squares Regression

Newton's Method Equation Solver

Compressibility Calculator

Units Conversion Calculator

Nomenclature Calculator


Related Information Links

Texas Instruments Calculators

Casio Calculators

Sharp Calculators

Hewlett Packard Calculators


Credits

Contact Webmaster


Practice Problem 1 Solution:

If only 0.25 molar NaOH and water are available, how much NaOH 
needs to be added to make 10 liters of 0.2 molar solution of NaOH? 

Answer= 8 liters.

One way to do the problem:
You're going to take a certain number of moles contained in a volume and put these moles in a total volume such that the final concentration is 0.2 molar. First we can determine how many moles are needed to make 10 liters of solution that are 0.2 molar:

10 liters * 0.2 moles/liter = 2 moles

Now that we know we need 2 moles of NaOH, we can see how many liters of 0.25 molar solution are need to have 2 moles of NaOH:

2 moles * 1 liter/0.25 moles = 8 liters

Another way to solve this problem is to use the equation:

Molaritynew= Molarityoriginal*Volumeoriginal/Volumenew

.20 = .25*Volumeoriginal/10

Volumeoriginal=8 L

Back to Practice Problems


Developed by
Shodor
in cooperation with the Department of Chemistry,
The University of North Carolina at Chapel Hill

Copyright © 1996-2008 Shodor
Please direct questions and comments about this page to
[email protected]